Subnetting IP dengan VLSM (Tugas V-Class Akhir)

Ada sebuah topologi seperti gambar berikut ini :

Dari gambar di atas terlihat 5 buah jaringan yang berbeda network dihubungkan dengan 3 buah Router, yakni router0, router1 dan router2. Hitung subnetnya :

* Network Management (32 Host) :

1. 32 host + 1 router + 1 alamat broadcast + 1 alamat network = 35
2. decimal 35 = biner 100011 = 6 bit
3. subnet masknya = 11111111.11111111.11111111.11000000 = 255.255.255.192
4. prefix = /26 , Network Address = 200.200.200.0/26
5. Total IP Address = 2^6 = 64 IP Address
   
6. Broadcast = 200.200.200.63
7. Range IP = 200.200.200.1 s.d 200.200.200.62

* Network HRD (16 Host) :

1. 16 host + 1 router + 1 alamat broadcast + 1 alamat network = 19
2. decimal 19 = biner 10011 = 5 bit
3. subnet masknya = 11111111.11111111.11111111.11100000 = 255.255.255.224
4. prefix = /27 , Network Address = 200.200.200.64/27
5. Total IP Address = 2^5 = 32
   
6. Broadcast = 200.200.200.95
7. Range IP = 200.200.200.65 s.d 200.200.200.94

* Network Administrasi (8 Host) :

1. 8 host + 1 router + 1 alamat broadcast + 1 alamat network = 11
2. decimal 11 = biner 1011 = 4 bit
3. subnet masknya = 11111111.11111111.11111111.11110000 = 255.255.255.240
4. prefix = /28 , Network Address = 200.200.200.96/28
5. Total IP Address = 2^4 = 16 IP Address
   
6. Broadcast = 200.200.200.111
7. Range IP = 200.200.200.97 s.d 200.200.200.110

* Network IT (4 Host) :

1. 4 host + 1 router + 1 alamat broadcast + 1 alamat network = 7
2. decimal 7 = biner 111 = 3 bit
3. subnet masknya = 11111111.11111111.11111111.11111000 = 255.255.255.248
4. prefix = /29, Network Address = 200.200.200.112/29
5. Total IP Address = 2^3 = 8 IP Address
   
6. Broadcast = 200.200.200.119
7. Range IP = 200.200.200.113 s.d 200.200.200.118

* Network Sales (16 Host) :

1. 16 host + 1 router + 1 alamat broadcast + 1 alamat network = 19
2. decimal 19 = biner 10011 = 5 bit
3. subnet masknya = 11111111.11111111.11111111.11100000 = 255.255.255.224
4. prefix = /27 , Network Address = 200.200.200.120/27
5. Total IP Address = 2^5 = 32 IP Address
   
6. Broadcast = 200.200.200.151
7. Range IP = 200.200.200.121 s.d 200.200.200.150

Hasil yang di dapat adalah :